What is the total inductive reactance of a parallel circuit with two inductors, one with 80 ohms and the other with 20 ohms?

To find the total inductive reactance of inductors connected in parallel, it's important to use the formula for combining parallel reactances. The total inductive reactance (X_total) can be calculated using the following equation:

1 / X_total = 1 / X1 + 1 / X2

where X1 and X2 are the reactances of the individual inductors. In this scenario, one inductor has a reactance of 80 ohms and the other has a reactance of 20 ohms.

Applying these values:

1 / X_total = 1 / 80 + 1 / 20

To combine these fractions, we first find a common denominator, which is 80 in this case:

1 / X_total = 1 / 80 + 4 / 80

1 / X_total = (1 + 4) / 80

1 / X_total = 5 / 80

Taking the reciprocal to find X_total gives:

X_total = 80 / 5 = 16 ohms.

Thus, the total inductive reactance of the parallel circuit with the two inductors is indeed 16 ohms. This calculation demonstrates that when inductors are in parallel, their