How much capacitive reactance would a 60 cycle circuit with an 88.464 microfarad capacitor have, rounded to the nearest whole number?

To find the capacitive reactance, you can use the formula:

[ X_C = \frac{1}{2\pi f C} ]

where:

• ( X_C ) is the capacitive reactance in ohms.

• ( f ) is the frequency in hertz (60 Hz for this problem).

• ( C ) is the capacitance in farads (88.464 microfarads, which is ( 88.464 \times 10^{-6} ) farads).

Substituting the given values into the formula:

1. Calculate ( 2\pi f ):

[

2\pi \times 60 \approx 376.99 \text{ radians/second}

]

2. Now plug in the values to find ( X_C ):

[

X_C = \frac{1}{376.99 \times 88.464 \times 10^{-6}}

]

3. Calculate ( 376.99 \times 88.464 \times 10^{-6} ) first:

[

376.99 \times 88.464 \times 10^{-6} \approx 0